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New Message on BDOTNET
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From: Joseph A Moraes
Message 4 in Discussion
Hi, I think you are trying to create Link Button Dynamically in the Datagrid. If so,
the problem for you could be rendering. It is trying to render a Server Control
outside the Form Tag. Try this equivalent, I think this may help you to an idea for
your error. Aspx <form id="frm1" runat="server"> </form> CodeBehind HTMLForm
oForm = Page.FindControl("frm1"); LinkButton oLink = new LinkButton(); oLink.ID =
"lnk"; oLink.Text = "LinkText"; oForm.Controls.Add(oLink); This snippet will add
the LinkButton to the Form. If I go anywhere wrong, let me know Thanks Joseph.
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