I only showed the individual write as an example that also does not work,
it only performs the very first serialWrite and ignores the rest.
Your example does work with various delays between each byte, but this will
work for me. I might still use the:
b.serialWrite(port, [
dio6Hi[0] ,dio6Hi[1] ,dio6Hi[2] ,dio6Hi[3] ,dio6Hi[4] ,dio6Hi[5]
,dio6Hi[6] ,dio6Hi[7] ,dio6Hi[8] ,dio6Hi[9],
dio6Hi[10],dio6Hi[11],dio6Hi[12],dio6Hi[13],dio6Hi[14],dio6Hi[15],dio6Hi[16],dio6Hi[17],dio6Hi[18],dio6Hi[19]
]);
command since it writes the bytes consecutive with no delay between each
byte and so is a little more efficient. At 9600 baud it took just over
20ms to send out the data without the delays between bytes and just under
200ms with the delays.
Thanks for the quick response. I learn something every time you post :)
On Tuesday, November 25, 2014 3:14:08 PM UTC-8, Jason Kridner wrote:
>
> On Tue, Nov 25, 2014 at 4:23 PM, John Mladenik <[email protected]
> <javascript:>> wrote:
> > Does anyone know an easier way to send a packet of hex data out the
> serial
> > port. Here is what works for me
> >
> > var dio6Hi = [0x7E, 0x00, 0x10, 0x17, 0x01, 0x00, 0x13, 0xA2, 0x00,
> > 0x40, 0xC0, 0xA9, 0x99, 0xFF, 0xFE, 0x02, 0x44, 0x36, 0x05, 0x72 ];
> >
> > b.serialWrite(port, [
> > dio6Hi[0] ,dio6Hi[1] ,dio6Hi[2] ,dio6Hi[3] ,dio6Hi[4] ,dio6Hi[5]
> > ,dio6Hi[6] ,dio6Hi[7] ,dio6Hi[8] ,dio6Hi[9],
> >
> >
> dio6Hi[10],dio6Hi[11],dio6Hi[12],dio6Hi[13],dio6Hi[14],dio6Hi[15],dio6Hi[16],dio6Hi[17],dio6Hi[18],dio6Hi[19]
>
>
> > ]);
> >
> > This will write all of the data in variable dio6Hi out of the UART in
> > order that I want. But I would like to do this or something like it:
> >
> > for (var i = 0; i < dio6Hi.length; i++) {
> > b.serialWrite(port, [dio6Hi[i]] );
> > }
> >
> > or even this:
> >
> > b.serialWrite(port, [dio6Hi[0]] );
> > b.serialWrite(port, [dio6Hi[1]] );
> > b.serialWrite(port, [dio6Hi[2]] );
> >
> > .
> > .
> > .
> > b.serialWrite(port, [dio6Hi[18]] );
> > b.serialWrite(port, [dio6Hi[19]] );
> >
> > Either of these do not work they only send out the first byte in dio[0]
> and
> > then stop. Is there any way with the serialWrite function to index the
> > variable with a "for" or other command in order to simplify sending out
> an
> > array of numbers?
>
> I believe your primary issue here is that the calls to b.serialWrite()
> are asynchronous and you aren't waiting for the writes to complete.
> I'm not really sure why you'd want to have individual calls to write
> each byte, but you could try something like:
>
> var i = 0;
> mySerialWrites();
> function mySerialWrites() {
> if(i < dio6Hi.length) {
> b.serialWrite(port, [dio6Hi[i]], mySerialWrites);
> i++;
> }
> }
>
> I haven't tested this, but I think it might be your issue. Let us know.
>
> >
> > --
> > For more options, visit http://beagleboard.org/discuss
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