You need to pay attention to data acquisition circuits that use a input mux and 
a sample and hold circuit like that used by the BBB analog circuits. When the 
ADC samples the analog input, it charges a small capacitor (sample and hold) 
and then the ADC converts the voltage stored in the capacitor. When the 
capacitor is connected to the input circuit, it represents a short circuit and 
then the capacitor charges based on the time constand t = rc, where r is the 
source impedance. This is apparent if the channel before is fully 0 or full 
scale as the capacitor in the sample an hold could be 0 or 1v8 or somewhere in 
between and that can affect the accuracy of your measurements.

A better approach is to use an opamp circuit as a voltage divider as it will 
present as a low impedance to the sample and hold circuit and eliminate bleed 
through from adjacent circuits. 

Regards,
John




> On May 30, 2017, at 4:32 PM, Dennis Lee Bieber <[email protected]> wrote:
> 
> On Tue, 30 May 2017 10:50:55 -0700 (PDT), philip k
> <[email protected]> declaimed the following:
> 
>> i'm attempting a build.  
>> 
>> I will be using 5 pressure sensors.  here are the specs:
>> 
>> Pressure Range: 0-200 psi
>> Output: 0.5V – 4.5V linear voltage output. 0 psi outputs 0.5V, 100 psi 
>> outputs 2.5V, 200 psi outputs 4.5V
> 
>       I'm presuming this is the critical specification...
> 
>> Working Temperature: -40—+125ºC;.
>> Accuracy: ±1%FS;
>> Thread: 1/8"-27 NPT.
>> Overload Capacity: 2 times;
>> Pressure Medium: The gas and liquid which is compatible with 316L stainless 
>> steel;
> 
>       Don't think knowing what size pipe thread it uses means much here...
> 
>> Load Resistance: ?(supply power-6.5V/0.02A)?;
> 
>       This might be important...
> 
>> Wiring: Red for IN+.  Black for GND.  Green for OUT.
>> 
>> would i be correct by running a 600? resistor parallel to each sensor to 
>> bring the voltage down to ?1.8v and go from pin 7 or 8 to the five sensors, 
>> then run sensor1 signal and a 600ohm resistor in parallel to pins P9 35, 
>> sensor2 signal and a 600ohm resistor in parallel to P9 36, and so on?
>> 
> 
>       I doubt it.
> 
>       What you most likely need is a voltage divider system (use fixed width
> font):
> 
> 4.5V  ------+
>                     |
>                     ~ ?1
>                     |
>                     + 1.8V ----->
>                     |
>                     ~ ?2
>                     |
> GND           ------+----------->
> 
> where ~ is resistor, values to be determined (do a Google on how to
> determine a voltage divider -- I'm not going to do all the work <G>)
> 
> {Unstudied: 4.5 / 1.8 = 2.5; say a 240Ohm for ?2, total needs to be 240*2.5
> => 600, so ?1 would be 600 - 240, or 360Ohm...}
> 
> -- 
>       Wulfraed                 Dennis Lee Bieber         AF6VN
>    [email protected]    HTTP://wlfraed.home.netcom.com/
> 
> -- 
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