Oh *SNAP*,

I think I may be on the wrong board. I just realized I have been using the 
BBGW instead of the Rev. C or BBBW. Crud. I will keep trying.

Seth

P.S. I will get back to everyone soon. Sorry for this issue. 



On Friday, July 7, 2017 at 7:52:26 PM UTC-5, Mala Dies wrote:
>
> Hello Rob,
>
> Seth here, again. I tried out the *(reading.value / 4096.0) * 1800;* in 
> the software. It tells me that I have a temperature of -49.99 degrees in 
> Celsius. I am trying to make believe my calculations from the software are 
> correct with the inside/climate controlled temp. in this house. 
>
> ...
>
> 49 degrees in Celsius is 120.xx in Fahrenheit. This seems extreme. It is 
> extreme. I have my temp on 80 degrees in Fahrenheit. I was expecting a 
> degree in Celsius of 26 or 27 from my reads. If you have any ideas, please 
> let me know. I am pretty sure you are very busy and do not have complete 
> time to dedicate to me. I understand completely.
>
> Seth
>
> P.S. Oh and I cut out the temp. transfer from Celsius to Fahrenheit in the 
> software. This is how the 49.xx came to be. I tried more than one TMP36 
> sensor. I will keep trying for this project I plan on keeping in time. 
> Oh...is there a type of ADC we are using that can be researched? Can I find 
> this ADC name and brand in the SRM?
>
> On Thursday, June 29, 2017 at 8:29:36 PM UTC-5, RobertCNelson wrote:
>>
>>
>>
>> On Thu, Jun 29, 2017 at 8:21 PM, Mala Dies <[email protected]> wrote:
>>
>>> Hello Rob,
>>>
>>> Seth here. I am located in the states. There is a big fault and I am not 
>>> clued in, obviously. How is F == C?
>>>
>>
>> Your values are correct:
>>
>> -39.58241C = -39.2483F
>>
>> -40C = -40F
>> 0C = 32F
>> 100C = 212F
>>
>>  
>>
>>> I figured that there would be a part to the software, the section that 
>>> displays the difference, that tells me/you the C and F reads. 
>>>
>>> Seth
>>>
>>> P.S. I am in about an 80 degree temp. right now. So, do I need to 
>>> replace "reading.value" with an actual numerical value? I will keep trying.
>>>
>>
>> var millivolts = reading.value * 1800;
>>
>> That's not right..
>>
>> var millivolts = (reading.value / 4096.0) * 1800;
>>
>> i think...
>>
>> Regards,
>>
>> -- 
>> Robert Nelson
>> https://rcn-ee.com/
>>
>

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