Thanks, this works! On Sunday, 29 December 2019 13:42:25 UTC, Patrick Ruckstuhl wrote: > > What I've done before that might work in your case is something like > > where joinstr(other_accounts) ~ ".*;Foo" > > Basically use a regexp against the joined string of the other accounts. > > On December 29, 2019 11:35:07 AM GMT+01:00, Red S <[email protected] > <javascript:>> wrote: > >Could you replace "X in other_accounts" with "number > 0"? > > >
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