ah, so you can't bury something that's not ready yet? --chad On Wed, Aug 10, 2011 at 10:29 PM, Daniel Olfelt <[email protected]> wrote:
> Yeah, I thought that would work, but bury works on the same objects that > delete does. I do know the ID of the job I am trying to delete from the > delay queue, but when I try to delete it, even though I know it is in the > queue, it returns NOT_FOUND. > > --Daniel > > On Wed, Aug 10, 2011 at 7:46 PM, Chad Kouse <[email protected]> wrote: > >> From reading the protocol doc - maybe you could work around it if you know >> the id. You might be able to bury and then delete the job. Not sure. >> >> --chad >> >> On Aug 10, 2011, at 8:21 PM, Daniel Olfelt <[email protected]> wrote: >> >> How hard would it be to add deleting of delayed jobs? Is there a reason it >> isn't an option? If it's just time, I might consider trying my hand at >> adding it. >> >> --Daniel >> On Aug 10, 2011 4:46 PM, "Chad Kouse" < <[email protected]> >> [email protected]> wrote: >> > Nothing I can think of that's too elegant. You could use memcached >> > though and stick a record in there relating to the delayed job. Then >> > when you want to delete the job just delete the associated memcached >> > object. And when you are consuming jobs check for the associated >> > record in memcached first. >> > >> > --chad >> > >> > On Aug 10, 2011, at 5:25 PM, Daniel < <[email protected]> >> [email protected]> wrote: >> > >> >> Is there any way to delete a delayed job, or modify a delayed job? I >> >> am trying to run several commands several minutes after user action, >> >> but if there is a duplicate job in delay, I do not want it to run >> >> twice. >> >> >> >> I know beanstalkd does not support deleting delayed jobs currently, >> >> but is there any sort of work around? >> >> >> >> - Daniel >> >> >> >> -- >> >> You received this message because you are subscribed to the Google >> Groups "beanstalk-talk" group. >> >> To post to this group, send email to <[email protected]> >> [email protected]. >> >> To unsubscribe from this group, send email to >> <beanstalk-talk%[email protected]> >> [email protected]. >> >> For more options, visit this group at >> <http://groups.google.com/group/beanstalk-talk?hl=en> >> http://groups.google.com/group/beanstalk-talk?hl=en. >> >> >> > >> > -- >> > You received this message because you are subscribed to the Google >> Groups "beanstalk-talk" group. >> > To post to this group, send email to <[email protected]> >> [email protected]. >> > To unsubscribe from this group, send email to >> <beanstalk-talk%[email protected]> >> [email protected]. >> > For more options, visit this group at >> <http://groups.google.com/group/beanstalk-talk?hl=en> >> http://groups.google.com/group/beanstalk-talk?hl=en. >> > >> >> -- >> You received this message because you are subscribed to the Google Groups >> "beanstalk-talk" group. >> To post to this group, send email to [email protected]. >> To unsubscribe from this group, send email to >> [email protected]. >> For more options, visit this group at >> http://groups.google.com/group/beanstalk-talk?hl=en. >> >> -- >> You received this message because you are subscribed to the Google Groups >> "beanstalk-talk" group. >> To post to this group, send email to [email protected]. >> To unsubscribe from this group, send email to >> [email protected]. >> For more options, visit this group at >> http://groups.google.com/group/beanstalk-talk?hl=en. >> > > -- > You received this message because you are subscribed to the Google Groups > "beanstalk-talk" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]. > For more options, visit this group at > http://groups.google.com/group/beanstalk-talk?hl=en. > -- You received this message because you are subscribed to the Google Groups "beanstalk-talk" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/beanstalk-talk?hl=en.
