Folks,
Sorry about the earlier post,
perhaps another newbie might get some benefit from this posting :)
Here is part of the revised code without the if{} block.
To see the exercise I have been working on point your browser to:
http://dowda.rockin.net/cgi/sql_sort3.pl
It does point another issue if two 'people' have same the birthday,
how do handle sorting the names!!!!!
Dave
---new----
.....other code deleted....
elsif ($sort_by == 1){
# sort by first name
&sort_name('first_name','last_name',);
}
elsif ($sort_by == 2){
# sort by last name
# &sort_name('last_name');
&sort_name('last_name','first_name',);
}
elsif ($sort_by == 3){
# sort by birthday
&sort_num('birthday');
}
elsif ($sort_by == 4){
# sort by Sex
&sort_name('sex');
}
sub sort_name() {
my ($first_field,$second_field) =@_;
foreach my $key (sort
{
($A) = $database{$a}{$first_field};
($B) = $database{$b}{$first_field};
($C) = $database{$a}{$second_field};
($D) = $database{$b}{$second_field};
(!$sort_direction) ? (lc($A) cmp lc($B) || lc($C) cmp lc($D)) : (lc($B) cmp lc($A) ||
lc($D) cmp lc($C));
} keys %database){
&print_tableData($key);
}
}
----old----
.....other code deleted....
elsif ($sort_by == 1){
# sort by first name
&sort_name('first');
}
elsif ($sort_by == 2){
# sort by last name
# &sort_name('last_name');
&sort_name('last');
}
elsif ($sort_by == 4){
# sort by Sex
&sort_name('sex');
}
sub sort_name() {
my ($A,$B,$C,$D,$which);
($which) = @_;
foreach my $key (sort
{
if ($which eq 'last') # sort last names
{
($A) = $database{$a}{last_name};
($B) = $database{$b}{last_name};
($C) = $database{$a}{first_name};
($D) = $database{$b}{first_name};
}
elsif ($which eq 'first') # sort first names
{
($A) = $database{$a}{first_name};
($B) = $database{$b}{first_name};
($C) = $database{$a}{last_name};
($D) = $database{$b}{last_name};
} else {
($A) = $database{$a}{sex};
($B) = $database{$b}{sex};
}
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