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Today's Topics:
1. Re: Long time no Haskell....simple typeclass question
(Nicholls, Mark)
2. Re: Long time no Haskell....simple typeclass question
(Nicholls, Mark)
----------------------------------------------------------------------
Message: 1
Date: Wed, 31 Dec 2014 11:15:29 +0000
From: "Nicholls, Mark" <[email protected]>
To: "[email protected]" <[email protected]>
Subject: Re: [Haskell-beginners] Long time no Haskell....simple
typeclass question
Message-ID:
<e7e7fdf32472ff48bb0e4d9dc4283d0e83849...@mtvne-exmb02.mtvne.ad.viacom.com>
Content-Type: text/plain; charset="us-ascii"
This is the basic problem...
I have a data type, that has some functions that require typeclass constraints
(this example doesn't...but that's not the point).
I have a typeclass, and I want to declare my datatype inhabits that type
class....
> data Func a b = Func (a->b)
> exeFunc :: (Ord a) => Func a b -> a -> b
> exeFunc (Func g) = g
> class IFunc f where
> exe :: f a b -> a -> b
> instance IFunc Func where
> exe = exeFunc
Follow your nose and obviously
"No instance for (Ord a) arising from a use of 'exeFunc'"
But how do I constain "a" in the instance declaration, when "a" doesn't even
appear
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Message: 2
Date: Wed, 31 Dec 2014 11:21:09 +0000
From: "Nicholls, Mark" <[email protected]>
To: "The Haskell-Beginners Mailing List - Discussion of primarily
beginner-level topics related to Haskell" <[email protected]>
Subject: Re: [Haskell-beginners] Long time no Haskell....simple
typeclass question
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I can obviously follow Haskell's advice and go...
> class IFunc f where
> exe :: (Ord a) => f a b -> a -> b
But that's not really what I want to say...that's constraining the class to
make it clear that the type inhabits it...not constraining the instance.
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