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Today's Topics:

   1.  LYAH example (sasa bogicevic)


----------------------------------------------------------------------

Message: 1
Date: Wed, 22 Mar 2017 12:44:23 +0100
From: sasa bogicevic <brutalles...@gmail.com>
To: The Haskell-Beginners Mailing List - Discussion of primarily
        beginner-level topics related to Haskell <beginners@haskell.org>
Subject: [Haskell-beginners] LYAH example
Message-ID: <34cd86b8-a4db-4776-8d88-05ff9f1c3...@gmail.com>
Content-Type: text/plain; charset=us-ascii

Hi All,
Can someone clarify the example I got from LYAH book. This let statement is 
kinda confusing to me : 

applyLog :: (a, String) -> (a -> (b, String)) -> (b, String)
applyLog (x, log) f = let (y, newLog) = f x in (y, log ++ newLog) 

I know that f applied to x should produce y and we append log with newLog but 
when reading  ... f x in (y, ...  I just don't see how f x becomes y in the let 
statement.
Seems more readable if we could write ... = (f x, log ++ newLog)

Thanks, Sasa

{
        name: Bogicevic Sasa
        phone: +381606006200
}





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