Thanks for that Steven,
I knew it was obvious
Gary
On Wednesday 25 April 2001 3:44 pm, [EMAIL PROTECTED] wrote:
> Gary,
>
> split uses the first argument as a regex, and the period is a
> metacharacter, and needs to be backslashed. Take a look at this
> snippet, which works:
>
> $test = 'L.svc.I.039558';
> ($dealer, $system) = split /\./,$test;
> print "$dealer\n$system\n";
>
> Steven Spears
>
>
>
>
> Gary Stainburn
> <gary.stainburn@ringw To: Perl
> Beginners <[EMAIL PROTECTED]> ays.co.uk> cc:
> Subject: missing
> something obvious 04/25/01 10:26 AM
>
>
>
>
>
> I know this is gonna be a daft one, but can anyone explain why the
> following code generates the output below.
>
> print "argv=$ARGV[0]\n";
> my($dealer,$system,$dtype,$ref)=split(".",$ARGV[0]);
> print"dealer=${dealer}\nsystem=${system}\ndtype=${dtype}\nref=${ref}\
>n";
>
> I've tried 1st without the braces, but it made no difference.
> Here's the output
>
> [docs@eddie docs]$ ./import L.svc.I.039558
> argv=L.svc.I.039558
> dealer=
> system=
> dtype=
> ref=
> [docs@eddie docs]$
> --
> Gary Stainburn
>
> This email does not contain private or confidential material as it
> may be snooped on by interested government parties for unknown
> and undisclosed purposes - Regulation of Investigatory Powers Act,
> 2000
--
Gary Stainburn
This email does not contain private or confidential material as it
may be snooped on by interested government parties for unknown
and undisclosed purposes - Regulation of Investigatory Powers Act, 2000
