Hi Jeff,
Thanks. According to the man pages Perl automatically substitutes + for +=
without fallback.
The problem is that even if I substitute the += method for + it still
doesn't work. Somehow $obj gets turned into the offset amount.
I have spent several hours with the debugger trying to find where this
happens. Any other clues?
regards,
Richard
At 10:47 3/06/2001 -0400, Jeff Pinyan wrote:
>Are you doing that via:
>
> fallback => 1
>
>in the argument list to 'use overload'? That's how the implicit
>definitions of operators work. It works for me:
