Re: $hash{$_}++

[Me]

> In simple cases, step 3 will happen momentarily,
> but if you haven't used it, then it will go away, and
> the new key won't be defined.
> 
> But if it's part of a larger expression that also
> dereferences out of the new element, then the
> new element will remain defined, even if that's
> not what you wanted.

Self-correction. I'm wrong. The above would only
apply if one was using ++$key. Sorry.