I forgot the beginning in my example:
$filename = <STDIN>;
chomp($filename);
$output = "$filename" . ".yyy";
$output =~ s/xxx/x/;
print $output;
Craig
[EMAIL PROTECTED]
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--------------------------------------------------------------
You will never find time for anything.
If you want time, you must make it.
Charles Buxton
----- Original Message -----
From: "Craig S Monroe" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Thursday, July 12, 2001 5:27 PM
Subject: Re: concatenate $FILENAME and .yyy
Didn't you say you wanted the file to be named x.txt.yyy?
how about?
$filename = "xxx.txt";
$output = "xxx.txt" . ".yyy";
$output =~ s/xxx/x/;
print $output;
Craig
[EMAIL PROTECTED]
Pager
Numeric: 1-877-895-3558
Email pager: [EMAIL PROTECTED]
--------------------------------------------------------------
You will never find time for anything.
If you want time, you must make it.
Charles Buxton
----- Original Message -----
From: "Jennifer Pan" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Thursday, July 12, 2001 4:49 PM
Subject: concatenate $FILENAME and .yyy
Hello all,
I stdin a file name: xxx.txt
and I would like to have a output file name called x.txt.yyy
This is how I do it
$FILENAME = <STDIN>;
$output = "$FILENAME.y";
print "$output";
And the result is only
.yyy
How do I concatenate $FILENAME and .yyy?
Thank you
