Re: Fw: changes visible when passing a list by value

[Jeff 'japhy/Marillion' Pinyan]

On Aug 10, Rizwan Majeed said:

>It is known that passing a list by value to a function does not make
>visible to the calling function changes made to the list.
>
>But I dont understand how does the push() function works. Push takes
>the value of a list and still makes visible to the calling block of code
>the changes to the list.

The push() function is internal.  It has a special bit of magic that
allows you to pass an array, and Perl will internally really have your
array, not just some copy of its elements.

You can the same effect with prototypes.  Please read the 'perlsub'
documentation about them.

-- 
Jeff "japhy" Pinyan      [EMAIL PROTECTED]      http://www.pobox.com/~japhy/
RPI Acacia brother #734   http://www.perlmonks.org/   http://www.cpan.org/
** Look for "Regular Expressions in Perl" published by Manning, in 2002 **


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