On Sun, 2009-06-21 at 07:16 -0700, John W. Krahn wrote: > EASY buzzhost.co.uk wrote: > > OK, I'm an idiot. I just cannot get a simple regex match to work as > > intended. I've google, I dug out my books of regex and Perl but I hang > > my head in shame and ask here for help; > > > > Take This line; > > > > Jun 14 08:14:41 pingpong postfix/smtpd[22386]: NOQUEUE: reject: RCPT > > from host120-109-dynamic.56-82-r.retail.telecomitalia.it[82.56.109.120]: > > 554 5.7.1 <t...@example.com>: Sender address rejected: spoofing of > > domain; from=<t...@example.com> to=<t...@example.com> proto=SMTP > > helo=<82.56.109.120> > > > > I'm trying to grab the email address in the 'from=<...' portion. I can > > pin this down with look ahead look behind; > > > > (?<=from\=<)....@.+(?=>) > > > > But it has a side effect of going to the last > on the line, not the > > closing half of the pair <>. > > > > To knock out the complications I drop to a simple pattern without the > > look ahead/behind; > > > > <....@.+> > > > > again it matches all the way to the end of the line, not just the > > opening < and closing > as intended. > > > > > > Now, a little research and I come up with 'greedy -v- non greedy' > > matching and thought I was on to something. But I can get that to play > > ball either; > > > > <....@.+(.*?)> > > > > But No dice. After 8 hours on this I'm starting to kick myself blue. Can > > anyone put me out of my misery? > > You need to make both sides of @ non-greedy: > > (?<=from=<)....@.+?(?=>) > > Or: > > <....@.+?> > > > > > John > -- > Those people who think they know everything are a great > annoyance to those of us who do. -- Isaac Asimov > John. I love you. I want to have your Babies. Thank you soo much! I don't understand WHY I have to do that, but it works and at this moment that is good enough for me!
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