Jenda Krynicky wrote:
But of course this does not print anything. The shift(@a) returns the
first element of @a which is zero, assigns that to $i and then checks
whether it's true. And of course it's not. So it skips the body and
leaves the loop. Keep in mind that the value of
my $i = shift @a
is NOT a true/false whether there was something shifted from the
array. It's the value that was removed from the array and assigned to
the $i. And if that value it false (undef, 0, 0.0, "0", "0.0", "" -
if I remember rigth) then the whole expression evaluates to false in
boolean context.
"0.0" is true:
$ perl -le'
for ( undef, 0, 0.0, "0", "0.0", "" ) {
print $_ ? "TRUE" : "FALSE";
}
'
FALSE
FALSE
FALSE
FALSE
TRUE
FALSE
John
--
Those people who think they know everything are a great
annoyance to those of us who do. -- Isaac Asimov
--
To unsubscribe, e-mail: beginners-unsubscr...@perl.org
For additional commands, e-mail: beginners-h...@perl.org
http://learn.perl.org/
