On Wed, Aug 19, 2009 at 08:59, Raheel Hassan<raheel.has...@gmail.com> wrote:
snip
> written thsi code, but the result of the command is not saving in the file ,
> any suggestions please.
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> my $result = 'service mysql start 2>>/var/log/comm.log';
snip

Your are using '' which is the single quoted string (i.e.
non-interpolating string), you mean to use `` which is the [command
execution string][1].  I would advise against using backticks for this
very reason.  Use the generalized form instead: qx//.  The slashes may
be replaced with any pair of characters, or in the case of bracketing
characters, the opposite bracketing character:

my $result = qx{service mysql start 2>>/var/log/comm.log};

snip
> if($result =~ /OK/)
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You also may want to use the [word-boundary zero-width assertion
(\b)][2] to ensure that you are matching the word OK not the substring
OK in a larger word like LOOK:

if ($result =~ /\bOK\b/)

[1] : http://perldoc.perl.org/perlop.html#Quote-and-Quote-like-Operators
[2] : http://perldoc.perl.org/perlre.html#Assertions

Chas. Owens
wonkden.net
The most important skill a programmer can have is the ability to read.

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