>>>>> "BRH" == Bryan R Harris <bryan_r_har...@raytheon.com> writes:
BRH> Maybe this is just my own ignorance on big-endian vs. little endian, but BRH> this code: BRH> print "big-endian: ", unpack("H*", pack("d", -3205.0569059)), "\n"; BRH> print "little-endian: ", unpack("h*", pack("d", -3205.0569059)), "\n"; BRH> prints: BRH> big-endian: e626c5221d0aa9c0 BRH> little-endian: 6e625c22d1a09a0c note that those are the same bytes but each byte is printed with different ordering for the hex digits. the docs say this: h A hex string (low nybble first). H A hex string (high nybble first). and a nybble (or nibble) is a single hex digit of 4 bits and there are two in a byte. the h vs H only changes the nibble order in a byte. this has nothing to do with endian issues which are a byte ordering thing. pack doesn't have a direct way to deal with endians with floats. you can just use reverse on the byte string to control that. that is what i do in Sort::Maker for this. did you look at that module yet? as i keep saying it does exactly what you are trying to do so you can learn from it. uri -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/