Just replying to add that you can use square brackets for an array literal:
$foobar = ['foo', 'bar']; See http://perldoc.perl.org/perlref.html#Making-References . John On Sat, Nov 28, 2009 at 5:53 AM, John W. Krahn <jwkr...@shaw.ca> wrote: > Mark_Galeck wrote: > >> Why does >> >> $foobar = \("foo", "bar"); >> print $$foobar; >> >> >> print "bar" ?? >> >> Thank you for any insight. Mark >> > > Because \("foo", "bar") is really (\"foo", \"bar") and the comma operator > in scalar context will return the last item listed so: > > $foobar = \("foo", "bar"); > > Is just: > > $foobar = \"bar"; > > > > > John > -- > The programmer is fighting against the two most > destructive forces in the universe: entropy and > human stupidity. -- Damian Conway > > > -- > To unsubscribe, e-mail: beginners-unsubscr...@perl.org > For additional commands, e-mail: beginners-h...@perl.org > http://learn.perl.org/ > > >
