[stuff cut out]
>> For example, if I'm populating a complex variable @d with
>> lots of pointers,
>> hashes, arrays, etc. within, if I populate that within a
>> subroutine, how do
>> I get it back out conveniently without it making a whole
>> nother copy of it
>> outside? If it's 500 MB, isn't that horribly inefficient?
>> Plus, I have to
>> keep track of it.
>>
> You pass as a refernce as ni
> called_sub(\...@d);
> Now when you update, you are updating @d and not a copy.
>
> If you have any questions and/or problems, please let me know.
> Thanks.
>
> Wags ;)
> David R. Wagner
So let's say I pass a reference to an array:
my @d = (1,2,3);
called_sub(\...@d);
... but then in called_sub, accessing that gets a lot "noisier", right?
sub called_sub {
my $d = shift;
push @{$d}, 2; # I'd rather be able to use @var instead of @{$var}
}
Is there any way to make a new variable, @something, that is just another
name for the array that was passed in by reference? Since I'm building a
complex data structure, having to include all those @{}'s can get annoying.
Also, if called_sub modifies that array that was passed in by reference,
does it stay changed outside the subroutine? Or do I have to return
something from the subroutine and capture it on the outside?
Thanks!!
- Bryan
ps. Out of curiosity, what does "wags" mean?
--
To unsubscribe, e-mail: [email protected]
For additional commands, e-mail: [email protected]
http://learn.perl.org/
