----- Original Message -----
From: "Owen" <rc...@pcug.org.au>
Newsgroups: perl.beginners
Hello Owen
To check the date passed with a script, I first check that the date
is in the format 20dddddd (20 followed by 6 digits exactly)
But the regex is wrong, tried /^20\d{6}/,/^20\d{6,6}?/,/^20\d{6,}?/ and
while a 7 or lesser digit number fails, eg 2009101, a 9 digit number,
like 200910103 does not fail.
unless ( $ARGV[2] =~ /^20\d{6}?/ ) { print
unless ( $ARGV[2] =~ /^20\d{6}$/) ...
If the end of line anchor is used, '$', the regex will accept an 8 digit
number if it's the only entry in $ARGV[2]
Chris
"$ARGV[2]\tdate format is YYYYMMDD, eg 20091031\n"; }
How do I get the regex to fail a 9 digit number
I suppose as a work around, I could say;
unless ((length($ARGV[2]) == 8) and ( $ARGV[2] =~ /^20/){fail}
TIA
Owen
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