>>>>> "SB" == Steve Bertrand <st...@ibctech.ca> writes:
SB> Am I correct in thinking that this:
SB> $url = $file =~ m{ (.*) /A/\d+.html }x;
SB> ...assigns '1' to $url because =~ binds tighter and assigns a 'true'
SB> value to $url, whereas:
SB> ( $url ) = $file =~ m{ (.*) /A/\d+.html }x;
SB> ...$url here is evaluated first, and assigned the actual string
SB> afterwards? iow, is it simply an arithmetic thing, that can also be seen
SB> as this:?
nope. it is scalar vs list context, not precedence.
the () makes the assignment to $url happen in list context. the m// op
in list context will return the list of grabs (with some variations
based on the /g modifier). in scalar context m// only returns a boolean
if the match succeeded or not.
SB> ( $url ) = ( $file =~ m! (.*) /A/\d+.html !x );
SB> D'oh! I just answered my own question. Learn something new everyday,
SB> even though it's a principle that I've known for years, but just didn't
SB> apply it...
that didn't change anything. =~ binds tighter than = anyway. it is still
context that does it.
SB> ( my $this ) = ( ( $url ) = ( $file =~ m! (.*) /A/\d+.html !x ) );
SB> print "$url :: $this\n";
that shouldn't make any difference to assigning $url in list context.
uri
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