Harry Putnam wrote:
my %h1 = (
'./b/f1' => 'f1',
'./b/c/fa' => 'fa',
'./b/l/c/f2' => 'f2',
'./b/g/f/r/fb' => 'fb'
);
my %h2 = (
'./b/fb' => 'fb',
'./b/c/fd' => 'fd',
'./b/l/c/f2' => 'f2',
'./b/g/f/r/fc' => 'fc',
'./b/g/h/r/fb' => 'fb'
);
In your previous example you used two different paths, so why does this
example have only one path and why do './b/l/c/f2' and './b/g/f/r/fb'
show up in both hashes but the other values do not?
John
--
The programmer is fighting against the two most
destructive forces in the universe: entropy and
human stupidity. -- Damian Conway
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