On 03/04/2011 18:35, shawn wilson wrote:
so, lets do what you asked (i like hashes better anyway:) )
my %hash3, %nothash;
my $found = 0;
while( my( $ikey, $ival ) = each( %hash1 ) ) {
while( my( $jkey, $jval ) = each( %hash2 ) ) {
if( ( $ikey == $jkey ) and ( $ival == $ikey ) ) {
$hash3{ $ikey } = $ival;
$found = 1;
}
}
if( $found == 0 ) {
%nothash{ $ikey } = $ival;
$found = 0;
}
not sure if that is any quicker and i just typed it, so it should work, but...
That is poor code and is a very long way from working. There is no exuse
I can think of for not testing a solution like this when the test data
has been provided for you. Be aware that this is - nominally at least -
a beginners group.
Rob
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