Hi, grow($part) returns an array, I don't know how to create a ref to array
in one step.
@$part = grow($part) doesn't work here.To my knowledge, it is used for
changing the array $part refers to, but $part is not a ref , it‘s a string,
it can't refer anything until it's changed to a ref.
$part = \(grow($part)) doesn't work either, it creates refs to elements in
the array.
2011/4/29 Uri Guttman <u...@stemsystems.com>
> >>>>> "zs" == z sway <zzway...@gmail.com> writes:
>
> zs> foreach $part (@part) {
> zs> $part =~ s/^\(|\)$//g;
> zs> my @temp = grow($part); #递归调用
> zs> $part = \@temp;
>
> no need for the @temp array. in fact if you name something temp, you
> likely don't need it at all.
>
> $part = [ grow($part) ] ;
>
> zs> my $a = $_[0];
>
> don't use $a (or $b) for your own variables. they are reserved for use
> by the sort function. also they are bad names in general as they don't
> tell the reader what they are for.
>
> uri
>
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