What is being told in here, is that:
foreach my $m (1..1e7 ) {
my @array;
foreach my $n (1..1e7 ) {
push @array, $n;
}
print "in\n";
}
print "sleeping\n";
sleep 600;
Stops growing in memory.
In normal execution, when the memory is no longer used, the OS will cache it.
Best Regards
Marcos
On Thu, May 19, 2011 at 14:26, Shawn H Corey <shawnhco...@ncf.ca> wrote:
> On 11-05-19 01:39 AM, Sheppy R wrote:
>>
>> how would you change the original code to get it to free up memory?
>
> Put the processing in a sub-process. When it dies, the memory is returned
> to the system.
>
> See:
> perldoc -f fork
> perldoc perlipc
>
>
> --
> Just my 0.00000002 million dollars worth,
> Shawn
>
> Confusion is the first step of understanding.
>
> Programming is as much about organization and communication
> as it is about coding.
>
> The secret to great software: Fail early & often.
>
> Eliminate software piracy: use only FLOSS.
>
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>
--
Marcos Rebelo
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