RaFaL has answered the question you asked, but it should be mentioned that
you are not using symbolic references in your code. \%hash is a hard
reference.
On Thu, Oct 18, 2001 at 09:33:06AM -0400, Ross Howard wrote:
> populate_hash (\%hash1, "HEY1", "value1");
> populate_hash (\%hash2, "HUMM", "HAH");
[snip]
> sub populate_hash ($$\%) {
> my $hash = $_[0];
> my $key = $_[1];
> my $value = $_[2];
>
> ${%{$hash}}{$key} = $value;
> }
The prototype ($$\%) dictates the subroutine gets three arguments: a scalar,
a scalar, and a hash that is enreferenced. Your example calls, however,
are: hash reference (which is a scalar), scalar, scalar. The only thing
preventing this from becoming a fatal error is that your prototype is
declared too late, which perl warns you about if you have warnings turned
on.
Perhaps you meant:
sub populate_hash (\%$$);
populate_hash(%hash1, "HEY1", "value1");
populate_hash(%hash2, "HUMM", "HAH);
sub populate_hash (\%$$) {
...
}
Michael
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Administrator www.shoebox.net
Programmer, System Administrator www.gallanttech.com
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