Hi xiyoulaoyuanjia,
Check my comments below.
On 7/12/12, xiyoulaoyuanjia <xiyoulaoyuan...@gmail.com> wrote:
> i am very sorry ！ i am intend to parse variable $a by the regular
> variable $b . in below way!
the below script will not give any output.
> ----------------------------------------
> $a="abc[0]";
> $b="bc[0]";
> $a=~/$b/;
> ---------------------------------------------
even if you decide to use:
print $a if $a=~m/$b/; #no output
> but it can not parse right ! just because the "[" symbol。 i kow
> $a=~/abc\[0]/ it can get right!
> but when regular is a varible . I do not know how to solve it？
to get what you wanted you will do might do this:
$a="abc[0]";
$b="bc[0]";
print $a if $a=~m/\Q$b\E/; # prints abc[0]
NOTE:
Please take note of the \Q and \E in the REs.
Don't use variable $a and $b, since these are default for sort
function. You will observe that without declaring these variables you
have your intended output (I suppose).
Others will say use strict and warnings pragma in your scripts,
however few the lines of codes.
> Sorry if this isn't clear let me know if there are any questions.
> thanks in advance！
>
>
> 2012/7/12 Jack Maney <jma...@adknowledge.com>
>
>> I don't understand what you're trying to say or do. Exactly what error
>> message are you getting?
>>
>> -----Original Message-----
>> From: xiyoulaoyuanjia [mailto:xiyoulaoyuan...@gmail.com]
>> Sent: Wednesday, July 11, 2012 10:54 PM
>> To: beginners@perl.org
>> Subject: regular error
>>
>> *hi all：*
>> * i have an error in below * regular
>> ----------------------------------------
>> $a="abc[0]";
>> $b="bc[0]";
>> $a=~/$b/;
>> ---------------------------------------------
>> how can i do in this way？
>> thanks ！
>> --
>> 继续上路。。
>> you can follow me at twitter
>> @xiyoulaoyuanjia
>>
>
>
>
> --
> 继续上路。。
> you can follow me at twitter
> @xiyoulaoyuanjia
>
--
Tim
--
To unsubscribe, e-mail: beginners-unsubscr...@perl.org
For additional commands, e-mail: beginners-h...@perl.org
http://learn.perl.org/
