Hi all,
Sorry about that.
Thank and best regards,
Jack Vo
On 7/26/2012 5:14 PM, Rob Coops wrote:
On Thu, Jul 26, 2012 at 12:05 PM, Jack Vo <jacksvo2...@gmail.com> wrote:
Hi all,
I need to compress many files in a directory on server. I use "awk" and
"zip" command to compress these files.
By "awk" command, I filter theses file :
*# ls -latr | grep iMAP.med0 | awk '{print $9}'*
iMAP.med0101_agent.trace.**20120726153046.tar.gz
iMAP.med0101_agent.trace.**20120726152942.tar.gz
iMAP.med0107_agent.trace.**20120726154526.tar.gz
iMAP.med0101_agent.trace.**20120726154741.tar.gz
iMAP.med0101_agent.trace.**20120726154616.tar.gz
iMAP.med0101_agent.trace.**20120726154436.tar.gz
iMAP.med0105_agent.trace.**20120726154555.tar.gz
iMAP.med0101_agent.trace.**20120726154532.tar.gz
iMAP.med0101_agent.trace.**20120726154700.tar.gz
iMAP.med0101_agent.trace.**20120726154720.tar.gz
I want to compress them to trace_file.zip, and I use the command, but can
not zip these files. Which parameters or syntax did I wrong ?
*# ls -latr | grep iMAP.med0 | awk '{ system("zip /tmp/trace_file" $9)}'*
# ls -latr /tmp/ | grep trace_file
#
--
Thank and best regards,
Jack Vo
Hi Jack,
Sorry but how is this related to perl? This is a linux/unix question that
most on this list might be able to answer but that does not mean it belongs
on this list.
Rob.
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