Hi, I am building a script to modify my LDAP directory and I want to use something like:
$mesg = $ldap->modify( $dn, replace => { description => 'New List of members', seeAlso => 'Some reference' } ); But I would like to build the list of replacements dynamically, that is, have a variable of the appropriate type, where I can first store "description" and "New List of members" then also store "seeAlso" and "Some reference"; and then only use that variable to do the replace. I have two questions: - What type should I use for the variable? - What will be the syntax for the $ldap->modify statement? Thanks in advance, Olivier -- -- To unsubscribe, e-mail: beginners-unsubscr...@perl.org For additional commands, e-mail: beginners-h...@perl.org http://learn.perl.org/