OK I see, thanks Gil.
I think the main problem is I don't know much about regex.
I will re-learn them this day.
On 2018/7/12 星期四 PM 10:02, Gil Magno wrote:
2018-07-12 20:50:22 +0800 Lauren C.:
thanks for the kind helps.
do you know what the expression in { } stands for?
^(\S+) - - \[(\S+).*\] \"GET (.*?/)\s+
Hi, Lauren
This is quickly explained in
http://perldoc.perl.org/perlrequick.html#Using-character-classes
\s (lowercase) stands for a "whitespace". \S (uppercase) stands for the
opposite of \s. So
$name = "lauren";
if ($name =~ m{\s}) { print 'it matched' }
This will not match, because there's no "whitespace" in the string. But this
$name = "lauren";
if ($name =~ m{\S}) { print 'it matched' }
will match, because in the string there is a character which is *not*
"whitespace".
For the ^ [] and .*? in the regex, those pages I the previous email help you.
Best
gil
On 2018/7/12 星期四 PM 8:37, Илья Рассадин wrote:
"m{ pattern }" is regular expression to parse log string.
It's equal to just "/ pattern /". Using different delimiter is convenient
here because usually symbol "/" must be escaped with backslash "\", but if
we use another delimiter - we can left "/" symbol unescaped and reges is
more readable.
You can further explore regex with this site https://regex101.com/r/4CGCcB/2
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