Dang, I could swear I tried that and it wasn't behaving like it was a ref. Now that I've tried it, I'll have to use it that way. Thanks a lot!
> -----Original Message----- > From: Bob Showalter [mailto:[EMAIL PROTECTED]] > Sent: Thursday, November 15, 2001 2:00 PM > To: 'Tomasi, Chuck'; '[EMAIL PROTECTED]' > Subject: RE: How to pass two hashes to a sub > > > > -----Original Message----- > > From: Tomasi, Chuck [mailto:[EMAIL PROTECTED]] > > Sent: Thursday, November 15, 2001 2:26 PM > > To: '[EMAIL PROTECTED]' > > Cc: '[EMAIL PROTECTED]' > > Subject: RE: How to pass two hashes to a sub > > > > > > Arg, I was hoping I wouldn't have to do that (not that I > > can't), but it > > would be much easier in some calls. I have a variable like > > "$ToMailAddr". > > Rather than setup a hash just to pass the value, it would be > > simpler for me > > to say: > > > > &mysub(%FromUser, {Address => $ToMailAddr}); > > > > where mysub is expecting two hashes, but really only uses the > > Address field > > from the second. If it must be references, it must be references... > > But > > {Address => $ToMailAddr} > > *is* a reference. It's a reference to an anonymous hash. > > So the call > > mysub(\%FromUser, {Address => $ToMailAddr}) > > passes two hash refs to mysub. (Note the \ added to the first arg). > -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
