On Friday 16 November 2001 01:36 pm, Etienne Marcotte rambled:
> > for(my $i = 2, my $j = 1; $i <= $last;$i++, $j++) {
> >         if ($j ne $fileNames[$i]) {
> >         print "Sending missing for file: $fileNames[$i]";
> >         &sendMissing($j);
> >         &pause;
> >          next;
> > }
>
> You never close the opening bracket in the if statement.

Actually that closing bracket IS for the if statement, it just didn't get 
indented in the cut & paste :-), there is more code in the for statement 
following the if.

> and your for is not perlish, more C code, but I won't attempt to clean
> it, I'm too beginner

That comes from asking a C++ guru for help ;-)

> for (2..$last) #for the i replacement
>         if ($_-1 != $fileNames[$_]) { # we can use != since it's only
> numbers
>           print "Sending missing for file: $fileNames[$_]";
>           &sendMissing($_-1);
>       } # your if ends there?
>         &pause; # or that too is in the if?
> }
>
> I am really beginner so I'll let the gurus code your sub way better, but
> that was my try.
> seeing your for, it's like j is always one under i since you initialize
> it at 1 and i at 2.

$i gets initialized to 2 so that it skips . and .. produced by reading the 
filesnames into an array (I'm sure theres a better way, but this works ;-)), 
$j starts at 1 since the first filename should be "1" 

I can send the whole script if need be, but it is rather long :-)

-- 
Michael D. Risser
Software Engineer/Linux Administrator
=============================
Machine Vision Products, Inc.
www.visionpro.com
[EMAIL PROTECTED]
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