split() doesn't modify the variable being cut up. So if you split $_ it
will not be modified. chop() on the other hand does modify it's argument
(or $_ if no argument is given).
My guess is that you are seeing code like this, or something like it:
foreach $item ( split(/,/, $_) ) {
# do stuff
}
split() takes the string argument, chops it up based on the given seperator,
and returns a list. So that code does the same thing as this:
@array = split(/,/, $_);
foreach $item ( @array ) {
# do stuff
}
I suggest posting a code example next time.
Cheers.
Rob
-----Original Message-----
From: David Milstead [mailto:[EMAIL PROTECTED]]
Sent: Friday, January 11, 2002 8:27 AM
To: [EMAIL PROTECTED]
Subject: Chop and Split
----- Forwarded by David Milstead/Raleigh/IBM on 01/11/2002 08:25 AM -----
Ask Bjoern Hansen
(via RT) To: David
Milstead/Raleigh/IBM@IBMUS
<[EMAIL PROTECTED] cc:
g> Subject: [netlabs #262]
[no subject]
Sent by: Bug
Tracker
<[EMAIL PROTECTED]
ooper.com>
01/10/2002 06:20 PM
Please respond to
list-owner
[[EMAIL PROTECTED] - Thu Jan 10 21:19:49 2002]:
Please send perl questions to the list ([EMAIL PROTECTED]). This
address is just for questions about the list. :-)
- ask
> I just subscribed to the beginner's mailing list and the message
said,
> "if you need to get in touch with the human owner of this list" to
send you
> an email.
>
> I have a question about "split" and "chop".
>
> If "split" is used on the $_ variable, what is left in the $_ variable
> after the split is performed?
> Is whatever was split from the $_ variable actually removed from
the $_
> variable?
> I'm trying to figure out a Perl script left by someone else and they
do a
> "chop" to remove a newline character
> and then a split to load some variables with data and the person
said that
> somehow it moves to the next record, so I'm
> thinking the split must remove from the $_ variable whatever you
told it to
> split. Is that right?
> I'm just learning this stuff.
>
> Thanks.
>
> David Milstead
> [EMAIL PROTECTED]
> 919-855-5242
>
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