I don't think this is the right way to approach this. I suggest you look at opendir, readdir in perlfunc.
opendir DIR, '/' or die "$0: no top level directory $!"; my @dirlist = readdir DIR; - Roger - ----- Original Message ----- From: "Russell Boyd" <[EMAIL PROTECTED]> To: ">" < <[EMAIL PROTECTED]> Sent: Thursday, January 31, 2002 8:16 PM Subject: pulling file name into perl I am wanting to get a unix directory file listing and put it into a Perl array. I attempted $date = system "ls -al | grep filename.txt"; However all this did was send it to <STDOUT>. What am I missing? Thanks, Russell -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
