On Feb 5, [EMAIL PROTECTED] said:
>Problem is I don't know how to escape the entire variable $value_a so that
>the . is not considered a quantifier.
You have $value_a and $value_b in the wrong place in your example.
Use \Q...\E around $value_b.
if ($value_b =~ /\Q$value_a\E/) {
print "true\n";
}
Or use the quotemeta() function:
$safe_a = quotemeta $value_a;
if ($value_b =~ $safe_a) { ... }
See:
perldoc -f quotemeta
perldoc perlop (for \Q)
--
Jeff "japhy" Pinyan [EMAIL PROTECTED] http://www.pobox.com/~japhy/
RPI Acacia brother #734 http://www.perlmonks.org/ http://www.cpan.org/
** Look for "Regular Expressions in Perl" published by Manning, in 2002 **
<stu> what does y/// stand for? <tenderpuss> why, yansliterate of course.
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