remember when calling a subroutine with & prepended, prototypes are never looked at.
> -----Original Message----- > From: Peter Scott [mailto:[EMAIL PROTECTED]] > Sent: Thursday, March 28, 2002 3:32 PM > To: Dave Storrs; Perl 6 Beginners list > Subject: Re: context of function calls > > > > >Perl 6 Beginners list <[EMAIL PROTECTED]> > ^^^ ahem? > > At 11:13 AM 3/28/02 -0800, Dave Storrs wrote: > >Executive summary: It looks like, no matter what context > foo() is called > >in, its arguments are always evaluated in list context. Is > this correct? > > Unless a prototype overrides it, yes. For instance, sprintf has an > implicit prototype that says it expects a scalar as its first > argument: > > % perl -le 'sub foo{ print wantarray ? "list" : "scalar" }; > sprintf(foo)' > scalar > > >I had always understood that: > > - a function's arguments were evaluated in the same > context as the > >context of the function (hmm...actually, thinking about it, > this seems > >like it can't be right. Is it simply always LIST, or can it vary?) > > For builtins, look at the signature in perlfunc. For your > own functions, > use a prototype to change it from LIST. In general, you need > a good reason > to do this. > -- > Peter Scott > Pacific Systems Design Technologies > http://www.perldebugged.com > > > -- > To unsubscribe, e-mail: [EMAIL PROTECTED] > For additional commands, e-mail: [EMAIL PROTECTED] > ---------------------------------------------------------------------------- -------------------- The views and opinions expressed in this email message are the sender's own, and do not necessarily represent the views and opinions of Summit Systems Inc. -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
