Timothy, et al -- ...and then Timothy Johnson said... % % Ok, I finally got a chance to test it, and the problem with my code is that % split expects a scalar as the second argument. This does work: % % ($temp) = $fullpath =~ m:/mp3/(.+):; % @working = split /\//,$temp; % % because it is taking the list returned by the match and assigning it to the % list with $temp as the only element. If I did this:
Hmmm... OK, so that explains it, but I still don't get it... So the
match is going to spit out a scalar but in order to use it you have to
capture it in a list context?
%
% $temp = $fullpath =~ m:/mp3/(.+):;
% @working = split /\//,$temp;
%
% then @working would be 1 because $temp is evaluating the list in scalar
% context, which returns the number of elements.
I saw that.
% DISCLAIMER: Someone please correct me if I am not using the appropriate
% terminology. The upside of what I mean is that if you do a $scalar =
% @array, then the variable $scalar now has the value of the number of
% elements in the array.
Right; that sounds familiar.
%
% Anyhoo, now we know why my suggestion didn't work. What we need to do, then
% is give split the first element of the list. Try this:
%
% @working = split(/\//,($fullpath =~ m:/mp3/(.+):)[0]);
That works perfectly, but I'm still fuzzy. So we match $fullpath and we
have to put it in () to bind the =~ properly, I suppose, and *that* is
what messes us up when we try to split and so we have to extract a scalar
from that list, and we do that with [0], right?
I tried {} and [] and nothing and none of them bound the =~ properly, so
it looks like () is the only way to do that. Is there a way to bind that
won't force a list context?
Thanks a bunch! & TIA & HAND
:-D
--
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