Ok, I am still having some problems with this...
Here is basically what I am doing...
In PHP:
Exec ("path/perlscript.pl", $var1, $returnvar)
Now this calls the perl script from PHP passing the perl script $var1 The
perl script then should run and give me $returnvar.
In Perl:
$var = @ARGV;
print "$var";
By just printing the $var to STDOUT in perl should give me the $returnvar.
However the $returnvar is empty when it is returned to PHP. My question is,
I am still a little iffy on the proper use of @ARGV
Could someone give me a quick explanation of how this exactly works.
Thanks
Scott
-----Original Message-----
From: drieux [mailto:[EMAIL PROTECTED]]
Sent: Monday, June 10, 2002 3:18 PM
To: Batchelor, Scott
Cc: begin begin
Subject: Re: Calling Perl script from php.
On Monday, June 10, 2002, at 12:58 , Batchelor, Scott wrote:
> I am using an exec command like this:
>
> Exec "perl.pl $variable"
>
> Scott
if you ran that at the command line,
#demo in /bin/sh constructs
variable="arg1 arg2 arg3"
perl.pl $variable
then your perl code either needs to walk through these
"command line arguments" directly with walking @ARGV
OR you may wish to look at
Getopt::Std and/or Getopt::Long
to use the more traditional ways of grovelling through
the @ARGV values - and dealing with what stuff is suppose
to be there with what flags and all...
does that help????
ciao
drieux
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