The case for $b = $b++ is actually $b = $b; $b = $b + 1; The case for $b = ++$b is $b = $b + 1; $b = $b ;
It depends on where the ++ operation's sequency to run. For evaluate this, you can try : print $b++; print " $b" ; # Result is "1 2" print ++$b; print " $b" ; # Result is "2 2" Hope this help, Smiley Connie =) ----- Original Message ----- From: "Michael Turner" <[EMAIL PROTECTED]> To: <[EMAIL PROTECTED]> Sent: Sunday, June 30, 2002 10:25 PM Subject: what happens with $b = $b++? > OK, here is a "real" beginners question, but interesting nonetheless: > > Sample code: > > $b = 1; > $b = $b++; > > Result: > > $b = 1 > > Which strikes me as a little surprising. Shouldn't the result be 2? What > is happening? > > If you respond, please CC me. Many TIA > > /Michael Turner > > > -- > To unsubscribe, e-mail: [EMAIL PROTECTED] > For additional commands, e-mail: [EMAIL PROTECTED] > > -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
