Try using a second variable to trace the values as it goes:
$a = 0
$b = 1
$a = $b++
print "$a=", $a, " $b=", $b
$a = 0
$b = 1
$a = ++$b
print "$a=", $a, " $b=", $b
From the Perl 5 Programmer's Notebook, Jesse Feiler, Prentice Hall, 2000:
When the autoincrement operator (++) is placed after the variable, it
is used (assigned) then incremented
When the autoincrement operator (++) is placed before the variable,
the increment is done before the variable is used
Hope that lessens the confusion
>> Michael> $b = 1; $b = $b++;
>> Michael> Result:
>> Michael> $b = 1
>>
>>$b++ is synonymous with $b = $b + 1. So, your second statement reads:
>>
>>'$b = $b = $b + 1'.
>>
>>If you replace your code with:
>>
>>'$b = 1; $b++;' or '$b = 1; $b = $b + 1', you'll get more expected
>>behaviour. :)
>>
>>- Chris.
>>--
>>
>
>
>Thanks for the response, Chris,
>
>but check this out:
>
>$b=1;
>$b = ++$b;
>result: 2
>
>So, that isn't the whole story. This has to do with pre- & post
>"timing", I think.
>
>/Michael Turner
>
>
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