> -----Original Message-----
> From: Nikola Janceski [mailto:[EMAIL PROTECTED]]
> Sent: Wednesday, July 31, 2002 11:27 AM
> To: Beginners (E-mail)
> Subject: regex capturing
>
>
> $\ = "\n";
> $date = "20020731";
> print join "/", ($date =~ /(\d{4})(\d{2})(\d{2})/)[1,2,0]; #
> this works
> print join "/", ($date =~ /(\d{4})(\d{2}){2}/)[1,2,0]; # this doesn't
>
> __END__
>
> why did the second pattern not capture the second occurance of \d{2} ?
But it does capture the second occurrence (the 31). It doesn't capture
the first (the 07).
In the absence of /g, it would seem that since there are only two
sets of parens in the second regex, only two values can be captured.
The {2} quanitifier would simply cause $2 to be "reused".
> Is this the correct action? or should it capture the second one in the
> second example?
> Is there a way to capture like so (like second example as I
> expected it to
> work)?
I would think /g would have to be used somehow, but I do not know
how.
Of course, the simple:
/(\d{2})/g
works, returning '20', '02', '07', '31'.
But that's not what you're after.
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