@array = grep !/^\s*$/, @array;
This will return an array of elements (removing all elements that are either filled
with spaces or are blank)
George.
i read that it wasnt so good to use this in ther perlfaq:
Please do not use
($is_there) = grep $_ eq $whatever, @array;
or worse yet
($is_there) = grep /$whatever/, @array;
These are slow (checks every element even if the first matches), inefficient (same
reason), and potentially buggy (what if there are regex characters in $whatever?).
//Dave
-----Original Message-----
From: George P. [mailto:[EMAIL PROTECTED]]
Sent: den 24 september 2002 13:39
To: David Samuelsson (PAC)
Cc: '[EMAIL PROTECTED]'
Subject: Re: regexp hides info?
On Tue, 24 Sep 2002, David Samuelsson (PAC) wrote:
> I have an array with a lot of data.
>
> i want to remove certain elements from it:
> so i ran:
> for (@array){
> s/$current_user.*//;
> }
>
> nw when i print it, all $current user are gone as i wanted, but its a big space in
>the array instead.
> like:
>
> user1
> user1
> user2
> user2
>
>
>
> user4
> user4
> user4
> etc..
>
> how do i get the array to be without the spaces, i tried to remove all whitespaces
>with s/\s+/, that didnt seem to work, any ideas?
>
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