Here '?!\s?not' after 'null' means 'null' is not followed by zero/one whitespace followed by 'not'. So the $+ will get 'null'. but if u want 'null knot' then write $str=~m/(null\s?knot)/ here the result will be 'null knot' --- RTO RTO <[EMAIL PROTECTED]> wrote: > Hello Friends, > > I am confused and hence coded a small RegEx > statement. > I am now having more questions. Would appreciate, if > you can help: > > Here is my code: > > C:\>perl -e "$str = 'null knot'; > $str=~m/(null(?!\s?not))/; print $+;" > > The Output is: > null > > Question 1: Should I not expect the full string > 'null > knot' to be printed? Why is just 'null' stored to > the > memory? > > If the string is: $str = 'null not', there is no > match > according to my expectation. Fine. > > Question 2: What would be my RegEx, if I want to > say, > "hey a string with TAT only if it is not preceded by > a > TIT"? I know that (?!<regex>) says, "match only if > not > followed by...". How would I do the opposite? > > Thanks, > Rex > > > > > __________________________________________________ > Do you Yahoo!? > Faith Hill - Exclusive Performances, Videos & More > http://faith.yahoo.com > > -- > To unsubscribe, e-mail: > [EMAIL PROTECTED] > For additional commands, e-mail: > [EMAIL PROTECTED] >
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