Larry
You're right - you should be using 'eq'. But I can't imagine why it's not
working.
Try hard-coding a value for $ip and trying it that way:
$ip = "192.168.100.377";
if ( $ip eq "192.168.100.100" )
{
&process_form;
}
else
{
&generate_form("NOT A VALID LOCATION");
exit;
}
Cheers,
Rob
----- Original Message -----
From: "Larry Sandwick" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Wednesday, November 27, 2002 6:17 PM
Subject: if statement not validating properly
>
>
> In the program below the if statement that qualifies the IP address
> never evaluates to be false, for what ever reason the form is always
> processed. Can anybody help me with this problem?
>
>
>
> The code should only allow computers with certain IP's to access the
> data to be processed. I know it sound different, but I have been asked
> to validate the IP's which are assigned by building location to access
> the data#!
>
>
>
> The first time through the code it will always generate the form, and
> the second time through it has the ip address and validates the IP and
> then processes the form if it has a valid IP.
>
>
>
> I have tried the code with "eq" and "==" and it makes no difference. I
> would think I need to use the "eq" because it is not a valid number...
> [uhm]I could be wrong...would not be the first time!
>
> It does not matter what the IP is; the "if statement" is always true and
> processes the form.
>
>
>
> Any suggestions would be appreciated.
>
>
>
> See code below
>
>
>
> TIA
>
> Larry
>
> #-----------------------------------------------------------------
>
>
>
> <begin snip>
>
>
>
>
>
> if ( $ip == "192.168.100.100" )
>
> {
>
> &process_form;
>
> }
>
> else
>
> {
>
> &generate_form("NOT A VALID LOCATION");
>
> exit;
>
> }
>
[snip function defs]
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