On Sat, Nov 30, 2002 at 09:55:19PM -0000, Chris Game wrote: > In an earlier post, Paul Johnson wrote: > > > On Sat, Nov 30, 2002 at 09:26:29PM -0000, Chris Game wrote: > > > >> Can anyone explain why > >> perl -e 'print reverse "forwards" ' prints "forwards"; and to get > >> what I want I have to use > >> perl -e 'print $var= reverse "forwards" ' which yields "sdrawrof" ? > >> Why do I have to introduce the extra variable just to get the print > >> I was after? > > > > Because your first example is in list context. > > > > perl -e 'print scalar reverse "forwards"' > > Blimey that was quick! Thanks for the response Paul. Why doesn't
:-) > perl -e 'print reverse scalar "forwards" ' work (I tried that earlier)? Because you want reverse to be in scalar context, not its arguments. -- Paul Johnson - [EMAIL PROTECTED] http://www.pjcj.net -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
