Hi Ben -
I have three general suggestions:
use strict;
use strict;
use strict;
'strict' forces you to pre-define your variables;
it makes the code more readable, AND will save you
many times over from misspelling errors (when this
happens, perl merrily creates a new variable with
the misspelled name and continues on its way - your
intended variable is not used - hard to find this
type of problem).
Your code would look like this with strict:
use strict;
use warnings; # put this guy in too - he will alert you to possible problems
sub HoA
{
my @temparray;
foreach my $arb (@uniqueroadname) {
foreach my $doublearb (@contents) {
if ($doublearb =~ m|$arb|) {
print "$arb ==== $doublearb\n";
push @temparray, $doublearb;
}
}
}
my %arrayref; # this is actually a hash from the syntax you use below
# oops! $arb is out of context! it was defined within
# the first foreach loop above!!?? - and has no meaning here,,,
$arrayref{$arb} = [@temparray];
}
Now, where do @uniqueroadmap and @contents
come from?
To answer you arrayref access question, get the
elements with this syntax:
my $ele0 = $arrayref{$arb}->[0];
my $ele1 = $arrayref{$arb}->[1];
You seem to be making all of this too hard. Maybe
you should start at the beginning again, an I will
help you simplify the solution.
Aloha => Beau.
-----Original Message-----
From: Ben Crane [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, December 03, 2002 12:05 AM
To: [EMAIL PROTECTED]
Subject: Hash Access Query
Hi,
right, my first attempt at a hash of arrays appears to
have some success...but I have a query:
sub HoA
{
foreach $arb (@uniqueroadname)
{
foreach $doublearb (@contents)
{
if ($doublearb =~ m|$arb|)
{
print "$arb ==== $doublearb\n";
push @temparray, $doublearb;
}
}
}
$arrayref{$arb} = [@temparray];
}
as far as I've tested, %arrayref contains ARRAY0x23233
-> etc...but I'm trying access that array:
$arrayref{$arb}[0] = will access the first array after
"following" a specific reference? Therefore, do I
access individual elements of that array through
$arrayref{$arb}[0][1]??
at the moment, the structure looks (i hope :) like
this:
%HASH - > Reference (roadname) -> Array 1
-> Array 2
-> Array 3
i reference the roadname which takes me to the next
tier, and then I can access all the arrays containing
info about that particular roadname (reference)...I
guess it's a one-many relationship...
Ben
__________________________________________________
Do you Yahoo!?
Yahoo! Mail Plus - Powerful. Affordable. Sign up now.
http://mailplus.yahoo.com
--
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
--
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
