Paul Johnson wrote: > But it might. The behaviour is undefined. The compiler may do as it > will. Google for "sequence point" if you want to find out more. > > The behaviour in Perl is undefined too, but more in the sense that the > behaviour has not been defined rather than that the behaviour has been > defined as undsefined. >
True, maybe. But I don't know what you mean by the behaviour in Perl is undefined. To me, the behaviour is well defined (ie, you won't find an exception where the above bahaviour will behaves differently). it's simply $i / $i which always gives you a 1 in Perl except where $i = 0 david -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
