On Fri, Jan 10, 2003 at 11:53:15AM -0600, Jensen Kenneth B SrA AFPC/DPDMPQ wrote:
> From: Tim Musson [mailto:[EMAIL PROTECTED]]
> >
> > JKBSAD> $one = 1;
> >
> > JKBSAD> ($one == 1) ? (print "\$one equals", print "$one") : (print
> > JKBSAD> "\$one does not ", print "equal 1");
> >
> > Why the double print statements?
>
> The two print statements were there for the sake of having 2 commands.
print "\$one equals", print "$one"
is just one statement. It is a print statement which prints a list.
The first element in the list is the string "\$one equals". The second
element is the result of the expression C<print "$one">. To determine
the result of that expression it is executed, with the side effect of
printing "$one". The return value is true (1 in this case) if the print
succeeded.
So the final list printed is ("\$one equals", 1).
> Seems to me that multiple commands are executed in reverse order (right to
> left).
No. Statements are always executed in the order they are encountered.
If that does not suit you, check out Befunge and other similar
languages ;-)
--
Paul Johnson - [EMAIL PROTECTED]
http://www.pjcj.net
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