"John W. Krahn" <[EMAIL PROTECTED]> writes:

>> >>   $rein_str = shift;
>> >>
>> >>   while(<>){
>> >>      chomp;
>> >>      $pre_out = $_;
>> >>      ($out = $pre_out) =~ s/$strp_re/$rein_str/;
>> >
>> >        ($out = $pre_out) =~ s/$strp_re/qq["$rein_str"]/ee;
>> 
>> I find no reference to `qq' used like this in `Programming Perl
>> [3rd]'.  Ditto for a double `ee' in this context.  I can sort of see
>> what is happing ... That is, $rein_str is being presented to the
>> interpreter in such a way that it knows how to read it.  But not
>> clear what all is happening here.
>
> The /e option eval()s the replacement string however, because you have
> back-reference variables ($1, $2, etc.) in the replacement string you
> have to wrap it in double quotes for each eval.

Probably being very dense here but something still confusing me.

qq means double quotes but then "" are already around $rein_str, so
do we have double double quotes?  And does 'ee' mean double eval? 
I think I'm still missing something basic here.


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